The light turns green, and a bicyclist starts forward with an acceleration of 1.2m/s^2 . How far must she travel to reach a speed of 8.0m/s ?
given a = 1.2 m/s^2 and also u = 0 m/s and v = 8.0 m/s
\[\large{v^2-u^2=2as}\]
so 26.7?
\[\large{64 = 2(1.2) s}\] \[\large{64=2.4s}\] \[\large{\frac{64}{2.4}=s}\] \[\large{\frac{640}{24}=s}\] \[\large{26.7 m = s}\]
good work @mandonut
i used the other formula
with at^2
you can use any formula but acc. to me this is easier
okay thanks
hmm weird..usually math slover goes on saying how these are physics questions...wonder why the change of heart
for that u must apply v = u + at first and then use the value of t
@lgbasallote that is because it includes the work of math and yes I was tired saying that all .. at last users continue that they want to do... so no response here
ahh welcome to the dark side
:D but this will not be in dark side..when I will recover myself with sickness
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