Question

Find the solution to this system using the substitution method. 2x -5y = -1 and x -3y = -3

Answer 1

2x-5y = -1

2x = -1 + 5y

x = \(\large{\frac{-1+5y}{2}}\)

Answer 2

put this value in the second eqn :
\[\large{x-3y=-3}\]
\[\large{\frac{-1+5y}{2}-3y=-3}\]

Answer 3

form the second equation we have x=3y -3 putting it in the first
we have 2(3y-3)-5y=-1
or 6y -6-5y =-1 or y=6-1
or y=5
hence x=3(5) -3=12
x=12 and y=5

Answer 4

\[\large{\frac{-1+5y-6y}{2}=-3}\]
\[\large{-1-y=-6}\]
\[\large{-1+6=y}\]
\[\large{5=y}\]

Answer 5

its too sticky and icky...mmmmmm

Answer 6

similarly find x

x- 3(5) = -3
x-15=-3

x = -3+15

Answer 7

got it @rannsan ?

Answer 8

I think so

Answer 9

Thank you!!