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Mathematics 12 Online
OpenStudy (anonymous):

How do I find the area between two functions? One is a parabola, the other linear.

OpenStudy (anonymous):

OpenStudy (lgbasallote):

do you know calculus?

OpenStudy (anonymous):

Still in the process of learning it but I don't have a strong knowledge.

OpenStudy (lgbasallote):

first...you need to know which area you're looking for

OpenStudy (anonymous):

I know I'm looking for the area that is enclosed by the linear function.

OpenStudy (lgbasallote):

well that's a good first step...next is you need to identify the equation of the curve and the line

OpenStudy (anonymous):

I already have haha or I wouldn't have been able to draw them. The parabola is y=0.02x^2-2x-4800 and the linear equation is y=2x-2800

OpenStudy (lgbasallote):

good...now identify...which one is on the top...the line? or the graph?

OpenStudy (ghazi):

|dw:1345973267188:dw| use double integration to find the area enclosed your function will be \[\int\limits_{-x}^{x}\int\limits_{x^2}^{x} dxdy\]

OpenStudy (anonymous):

the linear equation is the one on top?

OpenStudy (lgbasallote):

right

OpenStudy (ghazi):

limit of dx is from the equation of parabola in terms of x to the linear equation and limit of y is from left of x to the right ...that is the two points where line cuts parabola

OpenStudy (lgbasallote):

now use the formula \[\Large \int \limits_{x=a}^{x=b} [f(x) - g(x)]dx\] do you know that thingy?

OpenStudy (anonymous):

yeaahhh I have used that. where b and a are the upper and lower intersects?

OpenStudy (lgbasallote):

b and a are the left and right limits

OpenStudy (anonymous):

okay.

OpenStudy (lgbasallote):

wait.. a is left limit; b is right limit

OpenStudy (lgbasallote):

so what would your limits be>

OpenStudy (anonymous):

um, so it should end up looking something like \[\int\limits_{-200}^{-500}[(0.02x ^{2}-4x-4800-(-2x-2800)]\]

OpenStudy (lgbasallote):

nope...remember you said the linear equation was on top the curve?

OpenStudy (anonymous):

yeah?

OpenStudy (anonymous):

it crosses through the parabola at (-200,3200) and (-500,-1800)

OpenStudy (lgbasallote):

the top function is always the minuend

OpenStudy (lgbasallote):

\[\int (top - bottom)dx\] got it?

OpenStudy (anonymous):

Ohhh okay. So.. \[\int\limits_{-500}^{-200}[-2x-2800]-[0.02x^2-4x-4800)]\]

OpenStudy (anonymous):

dx at the end as well >.<

OpenStudy (lgbasallote):

right

OpenStudy (anonymous):

then can I just plug that into my calculator and get a result from there?

OpenStudy (lgbasallote):

yup. and according to mine..this is big

OpenStudy (anonymous):

I got -390000

OpenStudy (anonymous):

yep, same as my result. :)

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