How do I find the area between two functions? One is a parabola, the other linear.
do you know calculus?
Still in the process of learning it but I don't have a strong knowledge.
first...you need to know which area you're looking for
I know I'm looking for the area that is enclosed by the linear function.
well that's a good first step...next is you need to identify the equation of the curve and the line
I already have haha or I wouldn't have been able to draw them. The parabola is y=0.02x^2-2x-4800 and the linear equation is y=2x-2800
good...now identify...which one is on the top...the line? or the graph?
|dw:1345973267188:dw| use double integration to find the area enclosed your function will be \[\int\limits_{-x}^{x}\int\limits_{x^2}^{x} dxdy\]
the linear equation is the one on top?
right
limit of dx is from the equation of parabola in terms of x to the linear equation and limit of y is from left of x to the right ...that is the two points where line cuts parabola
now use the formula \[\Large \int \limits_{x=a}^{x=b} [f(x) - g(x)]dx\] do you know that thingy?
yeaahhh I have used that. where b and a are the upper and lower intersects?
b and a are the left and right limits
okay.
wait.. a is left limit; b is right limit
so what would your limits be>
um, so it should end up looking something like \[\int\limits_{-200}^{-500}[(0.02x ^{2}-4x-4800-(-2x-2800)]\]
nope...remember you said the linear equation was on top the curve?
yeah?
it crosses through the parabola at (-200,3200) and (-500,-1800)
the top function is always the minuend
\[\int (top - bottom)dx\] got it?
Ohhh okay. So.. \[\int\limits_{-500}^{-200}[-2x-2800]-[0.02x^2-4x-4800)]\]
dx at the end as well >.<
right
then can I just plug that into my calculator and get a result from there?
yup. and according to mine..this is big
I got -390000
http://www.wolframalpha.com/input/?i=int_-500%5E-200+%28-2x+-+2800+-+0.02x%5E2%2B+4x+%2B+4800%29dx
yep, same as my result. :)
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