Question

Need help ASAP!

Answer 1

u have to use the properties of logarithms:
\[ \large \log_a(AB)=\log_aA+\log_aB \]
\[ \large \log_a\frac{A}{B}=\log_aA-\log_aB \]
\[ \large \log_aA^n=n\log_aA \]

Answer 2

How would i do the first one?

Answer 3

ok let's see
\[ \large \log_5\frac{5}{8}+\log_5\frac{15}{1}+2\log_5\frac{4}{5}-\log_5\frac{2}{5}= \]

Answer 4

right??

Answer 5

right

Answer 6

applying the rules to the first summand what do u get??

Answer 7

Log\[\log[5](5/8)(15/1)(4/5)(2/5)\]

Answer 8

u forgot the 2 in front of the third log_5

Answer 9

and the minus in front of the 4th log_5

Answer 10

oh ok

Answer 11

log[5](5/8)(15/1)+2(4/5)-(2/5)

Answer 12

watch this
\[ \large =\log_5\left(\frac{5}{8}\cdot\frac{15}{1}\cdot\left(\frac{4}{5}\right)^2\cdot
\left(\frac{2}{5}\right)^{-1}\right) \]

Answer 13

ok so the 2 and the negative become exponents

Answer 14

yes!!
go ahead, and simplify the expression between the large parantheses

Answer 15

should i start with the exponents first?

Answer 16

yes, and factor anything that can be factored

Answer 17

would it be Log[5](15)?

Answer 18

yes and 15=3x5

Answer 19

go on finish it!!

Answer 20

15log5?

Answer 21

right

Answer 22

\[ \large =\log_515=\log_5(3\cdot5)=\log_53+\log_55= \]

Answer 23

=1.6826

Answer 24

well u r told that
\[ \large \log_53=0.682 \]
so i would drop the 6

Answer 25

ok