Question

Need help with Logs!!!

Answer 1

Why cant I open it?

Answer 2

idk hod on ill type it out

Answer 3

Find the solution set of 2log[3]x-3log[3]3=7 and log[3]x-2log[3]y=4

Answer 4

2log[3]x-3log[3]3=7

2log(3)x-3*1=7
2log(3)x=10
log(3)x=5
3^5 =x
x=243

Answer 5

got it?

Answer 6

Npw, substitue x in log[3]x-2log[3]y=4

Answer 7

and find y......... can u give a try?

Answer 8

oh ok ic

Answer 9

do i sub 243 into y as well?

Answer 10

Nope

Answer 11

U need to find y

Answer 12

ok well log[3](243)= 115

Answer 13

for #5, x = 9 and y = 1/3
Here just simplify the the log expert ion to simple simultaneous expert ion.

Answer 14

log[3](243)=5

Answer 15

log[3]=1215

Answer 16

for #6 A), x = 0 or x = 1
Here you need to change the expression to quadratic.

Answer 17

log=405?

Answer 18

and how would i cahnge it to a quadratic?

Answer 19

2^2x - 3 (2^x) + 2 = 0

Answer 20

then let 2^x be y, so as to get y^2-3y+2 = 0

Answer 21

finally #6 B), x = 5
Just use common simplification methods.