Question

find the inverse of the system...

Answer 1

y[n]= \[\sum_{k=-\infty}^{n}x(k)\]
options-
1.y(n)-y(n-1)
2.y(n)+y(n-1)
3.y(n)+y(n+1)

Answer 2

it's 1

Answer 3

@amistre64 , @mukushla

Answer 4

would u please explain it....am not getting how??

Answer 5

y[n]= \[y[n]=\sum_{-\infty}^{n} x[n] = x[n] +\sum_{-\infty}^{n-1}x[n] = x[n] + y[n-1]\]
so the inverted system is
\[x[n]=y[n]-y[n-1]\]