Question

please check this answer
\[\lim_{x \rightarrow +\infty} \frac{ 2^{4 } - 3x}{ x ^{4}+1}\]

x=10000
\[\frac{ 2*(10000)^{4} - 3*10000 }{ (10000)^{4} + 1}\] = \[- \infty\]

Answer 1

It is true

Answer 2

It is like
\[
-\ frac 3 {x^3{
\]

Answer 3

@Muskan please check again

Answer 4

divide both numerator and denominator with x^4. then apply the limits.

Answer 5

\[
-\frac 3 {x^3}
\]

Answer 6

When x is near Inifinty, the fraction is near - Infinity

Answer 7

\[\frac{ 2 }{ 1 }\]

Answer 8

muskan its\[\lim_{x \rightarrow +\infty} \frac{ 2x^{4 } - 3x}{ x ^{4}+1}\]ha?

Answer 9

yes

Answer 10

i think , it should be 2 then instead of -infinity.

Answer 11

when \(x\rightarrow \infty\)\[x^4>>x>>1\]so u can neglect \(3x\) in the num and \(1\) in denum In comparison to \(x^4\)

so\[\lim_{x \rightarrow +\infty} \frac{ 2x^{4 } - 3x}{ x ^{4}+1}=\lim_{x \rightarrow +\infty} \frac{ 2x^{4 } }{ x ^{4}}\]

Answer 12

thanks

Answer 13

The original question was
\[
\lim_{x \rightarrow +\infty} \frac{ 2^{4 } - 3x}{ x ^{4}+1}
\]
and this limit is zero