Ask your own question, for FREE!
Mathematics 9 Online
OpenStudy (anonymous):

Can someone help?

OpenStudy (anonymous):

|dw:1346005938423:dw|

OpenStudy (anonymous):

I need to find the domain in interval notation

jimthompson5910 (jim_thompson5910):

Hint: Since you can't take the square root of a negative number, this means that x(x-15) >= 0

OpenStudy (anonymous):

would I distribute that x?

OpenStudy (anonymous):

x^2-15>=0 x^2>=15

jimthompson5910 (jim_thompson5910):

you can, but think about it like this when is x(x-15) positive? We have 4 cases case 1) if x is positive and x-15 is positive, then x(x-15) is positive case 2) if x is negative and x-15 is positive, then x(x-15) is negative case 3) if x is positive and x-15 is negative, then x(x-15) is negative case 4) if x is negative and x-15 is negative, then x(x-15) is positive

jimthompson5910 (jim_thompson5910):

So you can see that x(x-15) is positive in case 1) and case 4)

OpenStudy (anonymous):

woah, that confused me...

jimthompson5910 (jim_thompson5910):

which part is throwing you off?

jimthompson5910 (jim_thompson5910):

Think of x and x-15 as factors of some number

jimthompson5910 (jim_thompson5910):

case 1) positive times positive = positive case 2) negative times positive = negative case 3) positive times negative = negative case 4) negative times negative = positive

jimthompson5910 (jim_thompson5910):

Does that make (a bit more) sense?

OpenStudy (anonymous):

yeah, just simple multiplication rules lol

jimthompson5910 (jim_thompson5910):

that's ok, I was confusing it a little bit

jimthompson5910 (jim_thompson5910):

To answer the original question, you have to find the interval where x is positive and x-15 is positive OR x is negative and x-15 is negative Optionally, you can graph x(x-15) or x^2 - 15 and see which portions of the graph are above the x-axis

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!