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Mathematics 23 Online
OpenStudy (anonymous):

Find the domain and range of h(x)

OpenStudy (anonymous):

OpenStudy (cwrw238):

the domain is the possible values of x range is the values of y the shaded circles indicate that these values are inclusive

OpenStudy (anonymous):

can you clarify a little more?

OpenStudy (anonymous):

The domain is the possible values for x. Since the function is continuous, it's simply from the furthest left x, to the furthest right x. Shaded circles means it includes that value. The range is the same as the domain, except you're dealing with y. What are the smallest and largest values of y?

OpenStudy (anonymous):

smallest is -2 and largest is 2?

OpenStudy (anonymous):

That would be your range, yes. Because those are the smallest and largest values of y. Bear in mind, this is because the function is continuous (no holes, steps, breaks, asymptotes, etc...)

OpenStudy (anonymous):

So, the range is (-inf,-2] U [2,inf) ?

OpenStudy (anonymous):

No, you have it backwards. You have everything that is NOT in the graph with that interval.

OpenStudy (anonymous):

backwards? [-2,-inf) U (inf,2] ?

OpenStudy (anonymous):

No :) You have everything that is NOT in the graph. In this notation, your range is simply: \[[-2, 2]\]

OpenStudy (anonymous):

So, -2 and 2 is not in the graph?

OpenStudy (anonymous):

What the interval [-2, 2] is saying is that the range includes all real numbers between -2 and 2, including both of them.

OpenStudy (anonymous):

the [] means "inclusive", and () means exclusive.

OpenStudy (anonymous):

ohh.. okay. isn't the domain exactly opposite?

OpenStudy (anonymous):

-3 and 3?

OpenStudy (anonymous):

The domain does the same, just on 'x', not 'y'. Here that is correct, your domain goes from -3 to 3

OpenStudy (anonymous):

(and includes them both)

OpenStudy (anonymous):

[-3,3] ?

OpenStudy (anonymous):

That's correct.

OpenStudy (anonymous):

now, how do I find the corresponding functions for h(1), h(3), h(-1), and h(2)?

OpenStudy (anonymous):

This is h(x), essentially what this means is substitute those numbers in for x. So, for h(1), just follow the x axis over to 1, and see what the corresponding y-value is.

OpenStudy (anonymous):

h(1)= 0

OpenStudy (anonymous):

That's correct, just repeat the process for the other values.

OpenStudy (anonymous):

okay :) thank you!

OpenStudy (anonymous):

Np.

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