Show that the function is not the derivative of any function on the interval -1<=x<=1
F(x)= 0, -1<=x<=0. And 1, 0<=x<=1
Hello
You must understand that derivative= slope-of-tangent-line
Hello....okay
BUT if a graph is to have a tangent it MUST, MUST MUST be without jumps or discontinuities (however this is NOT sufficient)
Your example is undergoing a jump - so no tangent is possible - neccessary for smoothness is at LEAST CONTINUITY !
You have a Stair-like graph - draw it !
So i get that much but how do I show that the function is not the derivative?
Oh sorry - the argument is as follows:
- You Assumption says that the function from which the "stair" is the derivative must have DERIVATIVE IN ALL THE POINTS OF [-1,1]
But Derivative - means , well-defined value of the derivative , whch is EQUAL from both "sides " of the point
However at point 0 - you do NOT have a well defined single value of the derivative - you have 2 one-sided limits which are NOT equall,. Which means derivative Does NOT exist at 0
The one-sided limits must be equal
So how do I SHOW that? Cause I understand tht It fails at 0 but I don't know how to show tht
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