Question

simplify the expression
(-4p)^2

Answer 1

hint: \[\huge a^{-m} \implies \frac{1}{a^m}\]
does that help?

Answer 2

not sure what am i suppose to do...

Answer 3

what is your a in this case?

Answer 4

-4

Answer 5

it's actually -4p <--that's your base

Answer 6

and what is m?

Answer 7

2

Answer 8

right. so what is the value of \[\huge \frac{1}{a^m}\]

Answer 9

so I just rewrite it in that form

Answer 10

yes. remember that a is -4p and m is 2

Answer 11

oh ok thanks

Answer 12

welcome

Answer 13

I don't think this is correct

Answer 14

the power here is not negative, your question is:\[(-4p)^2\]

Answer 15

which has a positive power

Answer 16

@lgbasallote - your example is for negative powers

Answer 17

wait...wasnt that negative a while ago?

Answer 18

I don't know? was it @aea2213 ?

Answer 19

am confused now lol

Answer 20

lgbasallote was asking if you had changed the question. did you originally post this question as:\[(-4p)^{-2}\]

Answer 21

no the exponent is not negative

Answer 22

ok, so then:\[(-4p)^2=(-4p)\times(-4p)=?\]

Answer 23

so its 16

Answer 24

what about the terms involving 'p'?

Answer 25

16p

Answer 26

\[p\times p=?\]

Answer 27

p

Answer 28

:/

Answer 29

recall your previous question where I stated the laws of indices

Answer 30

\[p\times p=p^1\times p^1=?\]

Answer 31

p^2

Answer 32

\[(-4p)^2=(-4p)\times(-4p)=?\]

Answer 33

16p^2

Answer 34

well done! that is correct. :)

Answer 35

yay lol thanks

Answer 36

yw :)