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a circle is tangent to the y-axis at y=3 and has one x-intercept ast x=1(a) determine the other x-intercept
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hmm.... one way i can see you do this is solve for the center, (x, y) by using the distance formula: \(\large \sqrt{(x-0)^2+(y-3)^2}=\sqrt{(x-1)^2+(y-0)^2} \) solve this equation for x and y ... then, since the radius is the x coordinate of the center, you can write down the equation for the circle and therefore find the other x-intercept.
yep... this is a multi-step problem....
so i can use any one distance formula which u have given right
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