Question

The formula P=0.68x^2 -0.041x+3 models the approx. population in thousands, for a species of fish in a local pond, x years after 1997.During what year will the population reach 27,234? I know how to set up the equation i just keep getting the wrong answer...the answer is 2003, but im not sure how to get to that

Answer 1

u r supposed to solve
\[ \large 27234=0.68x^2-0.041x+3 \]
right??

Answer 2

yes

Answer 3

rearranging u get
\[ \large 0.68x^2-0.041x-27231=0 \]
if u use the quadratic formula u have
\[ \large x=\frac{0.041\pm\sqrt{(-0.041)^2-4\cdot0.68(-27231)}}{2\cdot0.68} \]
right??

Answer 4

yeah

Answer 5

u got
\[ \large x_1\approx-200.084 \]
\[ \large x_2\approx200.144 \]
right??

Answer 6

yes

Answer 7

x is the number of years after 1997 so the answer would be
\[ \large 1997+x_2=1997+200=2197 \]

Answer 8

there must be something wrong with the wording of the problem then

Answer 9

Yeah Ive been trying to do this problems for forever so I totally agree lol. Thanks though!

Answer 10

u r welcome