Question

At time t hours after taking the cough suppressant hydrocodone bitartrate, the amount, A, in mg, remaining in the body is given by A = 14(0.8)t.
What percent of the drug leaves the body each hour?
How much of the drug is left in the body 2 hours after the dose is administered?
How long is it until only 1 mg of the drug remains in the body?

Answer 1

first of all allow me to know that what you tried?

Answer 2

.8+1=1.8 so .018%

Answer 3

but thats wrong

Answer 4

Do you actually mean \(A=14\cdot 0.8\cdot t\), or did you mean \(A=14t^.8\)?

Answer 5

A=14(0.8)^t

Answer 6

\[14(0.8)^T\]

Answer 7

@asnaseer may help u here..

sorry

Answer 8

the amount of drug in the body after t hours is given by:\[A=14(0.8)^t\]so, when t=0 (i.e. at the start), the amount in the body is given by:\[A=14(0.8)^0=14mg\]after each hour, the amount left in the body is multiplied by 0.8, which represents 80%.
so how much drug leaves the body each hour?

Answer 9

@Ldaniel I can only help if you respond to my questions.

Answer 10

20%

Answer 11

@asnaseer