Question

Show that \[\sqrt{x+2}\rightarrow2 \] as \[x \rightarrow \infty\]

Answer 1

I'll save you the trouble, it doesn't.

Answer 2

\[\lim_{x \rightarrow \infty} \sqrt{x+2} = \sqrt{\lim_{x \rightarrow \infty} x+2} = \sqrt{\infty + 2} = \sqrt{\infty} = \infty\]

I can apply the rule

\[\lim_{x \rightarrow \infty} f(x) = f(\lim_{x \rightarrow \infty}x)\]

because the function is continuous

look at the function

Answer 3

it will keep increasing to infinity look at the graph

Answer 4

Yeah sorry I got the question wrong.

Answer 5

no its ok, I hope my explanation was helpful

Answer 6

http://openstudy.com/study#/updates/503ad038e4b006c9390b445f