Question

(m^3*n)^-3/m^-7*n^8

Answer 1

\[\frac{(m^3n)^{-3}}{m^{-7}n^8}\] like that?

Answer 2

\[\frac{(m^3n)^{-3}}{m^{-7}n^8}\] first multiply the exponents in the numerator to get rid of the parentheses
\[\frac{m^{-9}n^{-3}}{m^{-7}n^8}\]

Answer 3

then since no doubt you want positive exponents only, you are going to bring everything to to denominator and change the signs of the exponents
\[\frac{1}{m^9n^3m^{-7}n^8}\]

Answer 4

then you are going to add the exponents
\[\frac{1}{m^{2}n^{11}}\] is your final answer