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Mathematics 6 Online
OpenStudy (anonymous):

What is the length, in units, of BD? 5 radical 6 5 6 radical 5 9

OpenStudy (anonymous):

OpenStudy (anonymous):

Use the proportion method.

OpenStudy (anonymous):

okay can you explain plz

OpenStudy (anonymous):

\[{x \over 12}={15 \over x}\] Cross multiply.

OpenStudy (anonymous):

Do you know how to use the proportion method?

OpenStudy (anonymous):

kinda not well

OpenStudy (anonymous):

|dw:1346072047425:dw|

OpenStudy (anonymous):

Do you see it now?

OpenStudy (anonymous):

yeah so what would be the answer

OpenStudy (anonymous):

it's basically two, congruent right angle triangles in one bigger right angle triangle.

OpenStudy (anonymous):

\[{x \over 12}\times {15 \over x}\]

OpenStudy (anonymous):

can you solve for x? Or do you still need help?

OpenStudy (anonymous):

can you show me

OpenStudy (anonymous):

To cross multiply, you need to multiply across. In this case, it would be \[x \times x=15 \times 12\]

OpenStudy (anonymous):

Then, find for x.

OpenStudy (anonymous):

is 180

OpenStudy (anonymous):

\[x^2=180\] \[x=\sqrt{180}\]

OpenStudy (anonymous):

correct.

OpenStudy (anonymous):

yeah if you 108 by 2 you 90 and again 42

OpenStudy (anonymous):

dived 180*

OpenStudy (anonymous):

now, what are the factors of 180 so it can be simplified even further? (one perfect square multiply by another number=180)

OpenStudy (anonymous):

90 is not a perfect square. Perhaps you can try again?

OpenStudy (anonymous):

42?

OpenStudy (anonymous):

Here's an example. Let's say you want to find the factors of 98 so that you can simplify \[\sqrt{98}\] , it would be \[\sqrt{49 \times 2}\]

OpenStudy (anonymous):

49 is a perfect square because 7 x 7 = 49

OpenStudy (anonymous):

42 is not a perfect square.

OpenStudy (anonymous):

yeah okay

OpenStudy (anonymous):

here I'll give you a hint... one number is 5

OpenStudy (anonymous):

what's the other number that you can multiply by 5 to get 180?

OpenStudy (anonymous):

so it answer is 5 radical of 6?

OpenStudy (anonymous):

\[{\sqrt{5 \times ?}} = \sqrt{180}\]

OpenStudy (anonymous):

not so fast.

OpenStudy (anonymous):

I would really like to help you understand a little so next time you will be better at answering questions like this. Please bear with me. We're really close.

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

what is... \[{180 \over 5} =?\]

OpenStudy (anonymous):

36

OpenStudy (anonymous):

Correct! Is 36 a perfect square?

OpenStudy (anonymous):

yes it is

OpenStudy (anonymous):

Ok. Now, you have your equation. \[\sqrt{5 \times 36}\] \[\sqrt{5} \times \sqrt{36}\]

OpenStudy (anonymous):

what is the square root of 36?

OpenStudy (anonymous):

sqaure root of 36 is 6

OpenStudy (anonymous):

Right! :) So now, we have... \[6 \sqrt5\]

OpenStudy (anonymous):

i think I found my answer it is 6 with a radical of 5

OpenStudy (anonymous):

Yup! :)

OpenStudy (anonymous):

Good job. Thank you for hanging in there.

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