What is the length, in units, of BD?
5 radical 6
5
6 radical 5
9
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OpenStudy (anonymous):
OpenStudy (anonymous):
Use the proportion method.
OpenStudy (anonymous):
okay can you explain plz
OpenStudy (anonymous):
\[{x \over 12}={15 \over x}\]
Cross multiply.
OpenStudy (anonymous):
Do you know how to use the proportion method?
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OpenStudy (anonymous):
kinda not well
OpenStudy (anonymous):
|dw:1346072047425:dw|
OpenStudy (anonymous):
Do you see it now?
OpenStudy (anonymous):
yeah so what would be the answer
OpenStudy (anonymous):
it's basically two, congruent right angle triangles in one bigger right angle triangle.
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OpenStudy (anonymous):
\[{x \over 12}\times {15 \over x}\]
OpenStudy (anonymous):
can you solve for x? Or do you still need help?
OpenStudy (anonymous):
can you show me
OpenStudy (anonymous):
To cross multiply, you need to multiply across. In this case, it would be
\[x \times x=15 \times 12\]
OpenStudy (anonymous):
Then, find for x.
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OpenStudy (anonymous):
is 180
OpenStudy (anonymous):
\[x^2=180\]
\[x=\sqrt{180}\]
OpenStudy (anonymous):
correct.
OpenStudy (anonymous):
yeah if you 108 by 2 you 90 and again 42
OpenStudy (anonymous):
dived 180*
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OpenStudy (anonymous):
now, what are the factors of 180 so it can be simplified even further? (one perfect square multiply by another number=180)
OpenStudy (anonymous):
90 is not a perfect square. Perhaps you can try again?
OpenStudy (anonymous):
42?
OpenStudy (anonymous):
Here's an example. Let's say you want to find the factors of 98 so that you can simplify \[\sqrt{98}\] , it would be \[\sqrt{49 \times 2}\]
OpenStudy (anonymous):
49 is a perfect square because 7 x 7 = 49
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OpenStudy (anonymous):
42 is not a perfect square.
OpenStudy (anonymous):
yeah okay
OpenStudy (anonymous):
here I'll give you a hint... one number is 5
OpenStudy (anonymous):
what's the other number that you can multiply by 5 to get 180?
OpenStudy (anonymous):
so it answer is 5 radical of 6?
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OpenStudy (anonymous):
\[{\sqrt{5 \times ?}} = \sqrt{180}\]
OpenStudy (anonymous):
not so fast.
OpenStudy (anonymous):
I would really like to help you understand a little so next time you will be better at answering questions like this. Please bear with me. We're really close.
OpenStudy (anonymous):
okay
OpenStudy (anonymous):
what is... \[{180 \over 5} =?\]
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OpenStudy (anonymous):
36
OpenStudy (anonymous):
Correct! Is 36 a perfect square?
OpenStudy (anonymous):
yes it is
OpenStudy (anonymous):
Ok. Now, you have your equation.
\[\sqrt{5 \times 36}\]
\[\sqrt{5} \times \sqrt{36}\]
OpenStudy (anonymous):
what is the square root of 36?
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OpenStudy (anonymous):
sqaure root of 36 is 6
OpenStudy (anonymous):
Right! :)
So now, we have...
\[6 \sqrt5\]
OpenStudy (anonymous):
i think I found my answer it is 6 with a radical of 5