Question

The 1st electron in the H2 atom is ejected from the atom after absorbing a total amt of Energy = 20.4eV . Calculate its de Broglie wavelenght in A^0

Answer 1

@UnkleRhaukus @mukushla @hartnn

Answer 2

\[E=hc/\lambda\]
Does that help?

Answer 3

i tried this,,,but did nt get...though

Answer 4

E = 20.4 - 13.6 = 6.8eV

Answer 5

*re-check calculation*
Because as far as I know, De-broglie's eqn has been well tested ~~

Answer 6

\[c=\nu\lambda\qquad \qquad\nu=\frac c\lambda\]
\[E=h\nu\qquad\qquad E=\frac{hc}\lambda\]
\[\lambda=\frac{hc}{E}\]
\[E = 20.4[\text{eV}]\]\[h=4.14×10^{−15}\left[\text{eV}\cdot\text {s}\right]\]\[c=3.00\times10^8\left[\frac{\text m}{\text s}\right]\]

\[\lambda=\frac{4.14×10^{−15}\left[\text{eV}\cdot\text {s}\right]\times3.00\times10^8\left[\frac{\text m}{\text s}\right]}{20.4[\text{eV}]}\]

Answer 7

^no, that doesn't take into account the binding energy required to liberate the electron.

Answer 8

\[609Å\]

what have i forgotten Jemurray3?

Answer 9

It absorbs 20.4 eV, but some of that goes into liberating it from the molecule.

Answer 10

So \(E=20.4[\text {eV}]-\text {binding energy of electron}\)

Answer 11

is that 13.7 eV?

Answer 12

it is E = 20.4 - 13.6 = 6.8eV

Answer 13

i think

Answer 14

To clarify, when you say H2 atom, you mean molecular hydrogen, right? Like, two hydrogen atoms bound together?