Please see attachment

Question

mathslover · Answer

Can any1 explain me this?

mathslover · Answer

@Xishem @asnaseer

mathslover · Answer

I made a guess since it was my test.. and fortunately I was correct but I do want to know the soln for the given quest.

anonymous · Answer

The great "Conservation of linear momentum" is the one you seek.

mathslover · Answer

denominator is having problem with me 

how does ti come with m + M

anonymous · Answer

mv=(m+M)v'

mathslover · Answer

md was sure for me since : 

md + 0 = M(v) + m(v')

anonymous · Answer

initial momentum: md + 0

final momentum: mv + Mv

equuate both

mathslover · Answer

@telltoamit that is my quest... 

why is velocity of bullet after collision = velocity of block after collision ? ? ?

anonymous · Answer

The bullet is assumed to be lodged in the block. Meaning that the bullet & the block travel together after collision.

mathslover · Answer

oh right so can that be 0 also ?

I mean that isn't it possible that the block and bullet does nt move after collision ?

anonymous · Answer

What!? Please explain...

anonymous · Answer

its possible only if te block is really heavy

mathslover · Answer

oh k so as u said that " the bullet is supposed to be lodged with the wooden block and hence the both will move with the same velocities... " 

I am saying that """"" 

isn't this possible that the bullet that is lodged to the wooden block does not move after the collision... 
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