Question

Kaitlyn runs on a triangular track in a local park. On Saturday, she runs one lap around track BAC. The length of each path on this track is shown in meters (m) in the diagram below.

If track DEF is similar in shape to track BAC, how many meters, rounded to the nearest tenth, would Violet run in one lap on track BAC? Type the numeric answer only in the box below.

Answer 1

similar triangles

\[\frac{BA}{DE}=\frac{AC}{EF}=\frac{CB}{FD}\]then insert numbers to find AC and CB

Answer 2

ok so what would the answer be for this one ?

Answer 3

\[\frac{BA}{DE}=\frac{AC}{EF}\]\[BA * EF= DE * AC\]\[22*13=11*AC\]then you got AC

\[\frac{BA}{DE}=\frac{CB}{FD}\]\[BA * FD= DE * CB\]\[22*9=11*CB\]then you got CB

Answer 4

whats cb tho

Answer 5

line CB :c in triangle BAC

Answer 6

so it would be 4

Answer 7

what is 4? why 4?

Answer 8

yea its not 4 ? what is it then

Answer 9

CB is 22 * 9 / 11 = 18
AC is 22 * 13 / 11 = 26

BA is 22 as given

add those up and round up nearest tenth

Answer 10

44?

Answer 11

Line segment AC is parallel to ED. . Solve for x. Round to the nearest tenth.

Answer 12

why do you conclude they are parallel? it's not given in the question. it's given that BAC is similar to DEF.

and 18 + 26 + 22 = 66, rounds up to 70. 70 is the answer to the original question

Answer 13

ah new question =.=. .......

Answer 14

yea thats what i got . could you help me with the next problem?

Answer 15

it's another case of similar triangles
triangle BED is similar to BAC because all their angles are equal.

\[\frac{BA}{BE}=\frac{AC}{ED}= \frac{CB}{DB}\]

Answer 16

i figured it out it x = 21.7

Answer 17

yup ur'right