Question

32. If 0 < n < 1, which of the following gives the correct ordering of n,n,and n2?

(A) n < n < n2 (D)n 13 years ago

Answer 1

look at question 32

Answer 2

here is a trick if you get confused
since you are not given numbers, clearly it doesn't matter what they are. so pick one, find the answer, and it will be right no matter what

Answer 3

i dont get it

Answer 4

i pick \(n=\frac{1}{4}\) so \(n^2=\left(\frac{1}{4}\right)^2=\frac{1}{16}\) and \(\sqrt{n}=\sqrt{\frac{1}{4}}=\frac{1}{2}\)

Answer 5

now we order them, and whatever answer we get will be the right one
this is a good trick to know for standardized tests

Answer 6

i get
\[\frac{1}{16}<\frac{1}{4}<\frac{1}{2}\] so
\[n^2<n<\sqrt{n}\] must be correct

Answer 7

btw i picked \(\frac{1}{4}\) because it was easy to take the square root

Answer 8

so it's E

Answer 9

i didn't look at the answers

Answer 10

ok