Question

ds

Answer 1

How do I do part B?
@UnkleRhaukus

Answer 2

For the first one we just take the deriv of each thing right?

Answer 3

yeah i think so , tell me what you get for a

Answer 4

for veloctiry i get <cos(t)/2, sqrt(3) cost/ 2, -sin(t)>
acceleration <-sin(t)/2,-sqrt(3) sin(t) /2 , -cos(t)>

Answer 5

what are your three co-ordinates

Answer 6

what do you mean?

Answer 7

didnt i just write them out

Answer 8

\[\langle x,y,z \rangle\]or\[\langle\rho,\theta,\phi\rangle\]

Answer 9

I just put out the xyz

Answer 10

But how would I do part b ofthis?

Answer 11

I am faily sure a is right

Answer 12

if it is x,y,z

you should be able to tell me the equation of a sphere in these co-ordinates,
dont forget r^2=

Answer 13

x^2 + y^2 + z^2 = r%2

Answer 14

the left hand side is constant you have a sphere

Answer 15

why is it left

Answer 16

if the left hand side is constant you have a sphere

Answer 17

constant*

Answer 18

p=<x,y,z>=<sin(t)/2, sqrt(3) sin(t) /2 , cos(t)>

Answer 19

square each component and add, if you have a number that is constant you have a shpere

Answer 20

do i plug in the number 1 for t?

Answer 21

no leave t as t

Answer 22

then how i prove it equals 1 from the origin

Answer 23

\[\left(\frac{\sin(t)}2\right)^2+ \left(\frac{\sqrt 3 \sin(t)} 2\right)^2 +\cos^2(t)\]
\[=\]
\[=\]

Answer 24

if you get it right \(t\) will magically drop out of the equation
using some trig identity