In the figure below, the length of is 64 units and the length of is 137 units. What is the length of ?
Hello so you have a SIMILARITY PRINCIPLE and Equation to define
Sorry NO similarity -just trigonometry
64 is Opposite 45 - ==> it is Sin 45 * LeftBase (we call it now simply L for short, and the Right base will be R)
(L / Cos 45) = CA
CA*Sin 45 =CB
|dw:1346081185338:dw| \[\tan 45= \frac{ 64 }{ x}\]
Thus L *SIn45/Cos45 = CB = 64
Soo L * Tan 45 = 64
L = 64 / tan 45
@Mikael tan45=1 substitute!
Then Just Substract : 137 - L ( that you found)
you need to use one of these sine cosine or tangent
i am so confused.
If you are required to f. the EG
use tangent sustitue the numbers you have with the formula of tangent
"Nice to be a King" (song)
so what is the length of ea
I HAVE SHOWN U HOW TO COMPUTE the EG
It is the Cos side , where the hypothenuse is EA
Soo just Divide EG/Cos 60 (and remark to any Royals reading: don' spoil the fun for the Seeker-of-Answers please...)
I remind you that EG was denoted R in my notation where R + L =137
is the anwer 146
With all due humblness - please grant me a medal bfowler344 . It is well earned
of course. i wouldnt not give you one. you have helped me. thank you
BTW if you "fan" me - i would gladly help with more trigonom/geometr problems. Thank U in advance
you'll get x= 64 now |dw:1346081897415:dw| \[\tan 60 = \frac{ h }{ 73 }...h= \sqrt 3*73=126.436\] is your answer
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