The 1st electron in the H2 atom is ejected from the atom after absorbing a total amt of Energy = 20.4eV . Calculate its de Broglie wavelenght in A^0 (mass of electron is 9.1 *10^-31 kg)

Question

The 1st  electron in the H2 atom is ejected from the atom after absorbing a total amt of Energy = 20.4eV . Calculate its de Broglie wavelenght in A^0 (mass of electron is 9.1 *10^-31 kg)

anonymous · Answer

@ghazi

anonymous · Answer

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ghazi · Answer

ok..wait a sec dude :)

ghazi · Answer

first of all angstrom= 10^-10 m is that okay?

ghazi · Answer

then $$E= \frac{ h*c }{ \lambda }$$ but it would be great if you can convert this eV

ghazi · Answer

1eV= 1.60217646 × 10^-19 joules

anonymous · Answer

but that does nt work..))

anonymous · Answer

i did..this 1 st time....and  let me recheck it..

anonymous · Answer

mass is given in the question (electron)

anonymous · Answer

i think we shuld use it...

ghazi · Answer

$$32.6808* 10^{-19}=\frac{ 6.626*10^{-34}*3*10^8 }{ \lambda }$$

anonymous · Answer

u would get 60.... some thing

anonymous · Answer

but the answer shuld be 4.7 A

anonymous · Answer

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