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Solve the radical, and check all proposed solutions:
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\[\sqrt{18x-9}=x+4\]
Square both sides first. Let me know what you get
\[18x-9=x ^{2}+16\]
You squared the right side incorrectly
You were supposed to get \[18x-9=(x+4)^2\]
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Now, expand the right side.
18x-9=(x+4)(x+4)?
Okay, now multiply the right side.
x^2+8x+16
\[0=x ^{2}-10x+25\]
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Okay, now factor the right side.
What happened?
It froze up..0=(x-5)(x-5)
Which is the same thing as \[0 = (x-5)^2\] Now take the square root of both sides.
What?
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Do you know what a square root is?
Take the radical of both sides.
\[\sqrt{0} = \sqrt{(x-5)^2}\]
Don't tell me you've never seen that before.
Oh, Okay, I have, but it just looked wrong
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Okay, so what is the result of that?
15?
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