Can someone help me solve 92 29/30 - 15 13/15? I know the common denominator would be 15...
subtract the whole numbers subtract the fractions
\(\huge 92\frac{29}{30} - 15\frac{13}{15}\)
its like above ?
yes, just like that!
you can write the same as : \(\huge (92 + \frac{29}{30}) - (15 + \frac{13}{15}) \)
you can group the whole numbers, and fractions separately
\(\huge (92 - 15) + (\frac{29}{30} - \frac{13}{15})\)
does this make sense so far ?
You stole my method @ganeshie8, but I'm cool with it. :P
lol i stole your many methods :P
okay so the fraction would be 16/15?
nopes... while subtracting fractions, you need to make denominators common
the fraction part : \(\huge (\frac {29}{30} - \frac{13}{15})\) \(\huge (\frac {29}{30} - \frac{13*2}{15*2})\) \(\huge (\frac {29}{30} - \frac{26}{30})\)
now since the denominators are same, you can subtract numerators !!
oh okay, so the answer is 77 3/1? I'm confused with the 30
okay.... 30 is just the LCM or common-denominator 77 3/30 you can simplify further, 3 goes in 30
77 1/10?
thats right ! good work :P btw, did you get that 30 thingy in fraction part... ?
Oh I meant subtracting 30 - 30
oh denominators we dont subtract. below next steps for fraction part, see if it helps :
\(\huge \frac {29}{30} - \frac{26}{30} \) \(\huge \frac {1}{30}(29-26) \) \(\huge \frac {1}{30}(3) \) \(\huge \frac {3}{30} \) \(\huge \frac {1}{10} \)
once we have the common denominator of 30, we factored out 1/30 and subtracted 29-26
okay, thank you!
np :D
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