48.0g piece of metal is dropped into 50.0mL of water in a graduated cylinder. The water level rises to 62.4mL. What is the density of the metal?
first find the volume \[V = V_F - V_1\] your final volume is 62.4 mL and initial volume is 50.0 mL so... \[\implies V = 62.4 - 50.0\] simplify... \[\implies V = 12.4 \; \text{mL}\] now to get density use the formula \[\rho = \frac MV\] here, mass is 48.0 g so density is \[\implies \rho = \frac{48.0 \; g}{12.4 ~ mL}\] use a calculator to solve dies that help?
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use your calculator and solve what i wrote....
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