An easy way to find the distance between a point (x,y) and a line (ax + by = c)?
you use the distance formula:\[d={\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}}\]
right, but that's from two points. so if you have an equation like y = 2x + 6 and a point, say, (3,4) then how would you find the difference?
*distance, sorry
convert the line from ax+by=c form to y=mx+b form and graph it
help him out @sami-21 :)
the distance formula from point (x,y) to line ax+by+c =0 is \[\Large d=\frac{|ax+by+c|}{\sqrt{a^2+b^2}}\] for example if i have to find the distance from (3,2) to line 3x+4y+9=0 here a=3, b=4, c=9 , x=3,y=2 so distance will be \[\Large d=\frac{|(3(3)+4(2)+9|}{\sqrt{(3)^2+(4)^2}}=\frac{|26|}{\sqrt{25}}=\frac{26}{5}\]
@MSMR is it ok now ?
Thank you! Wow, that must have taken a lot of time to make on the equation editor. Thank you so much, I'll be sure to memorize that formula. Thanks to you and @yummydum!
you are welcome :)
i didnt do much but youre welcome! :)
credit goes to @sami-21 :D
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