Ask your own question, for FREE!
Mathematics 13 Online
OpenStudy (msmr):

An easy way to find the distance between a point (x,y) and a line (ax + by = c)?

OpenStudy (anonymous):

you use the distance formula:\[d={\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}}\]

OpenStudy (msmr):

right, but that's from two points. so if you have an equation like y = 2x + 6 and a point, say, (3,4) then how would you find the difference?

OpenStudy (msmr):

*distance, sorry

OpenStudy (anonymous):

convert the line from ax+by=c form to y=mx+b form and graph it

OpenStudy (anonymous):

help him out @sami-21 :)

OpenStudy (anonymous):

the distance formula from point (x,y) to line ax+by+c =0 is \[\Large d=\frac{|ax+by+c|}{\sqrt{a^2+b^2}}\] for example if i have to find the distance from (3,2) to line 3x+4y+9=0 here a=3, b=4, c=9 , x=3,y=2 so distance will be \[\Large d=\frac{|(3(3)+4(2)+9|}{\sqrt{(3)^2+(4)^2}}=\frac{|26|}{\sqrt{25}}=\frac{26}{5}\]

OpenStudy (anonymous):

@MSMR is it ok now ?

OpenStudy (msmr):

Thank you! Wow, that must have taken a lot of time to make on the equation editor. Thank you so much, I'll be sure to memorize that formula. Thanks to you and @yummydum!

OpenStudy (anonymous):

you are welcome :)

OpenStudy (anonymous):

i didnt do much but youre welcome! :)

OpenStudy (anonymous):

credit goes to @sami-21 :D

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!