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How do you factor the expression 2x^2-5x-3
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break down the middle term first \[\implies 2x^2 - 6x + x - 3\] now group \[\implies (2x^2 - 6x) + (x-3)\] now factor each group \[\implies 2x(x - 3) + (x-3)\] now factor out \[\implies (x - 3)(2x+1)\] does that help?
What do you mean factor out
take the common factor and factor it out
in the case of 2x(x-3) + (x-3) the common factor is (x-3) so you "factor it out" got it?
What steps do you take in factoring something out
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breaking down the middle term...?
I'll be more specific. How did you go from that to (2x+1) (x-3)
|dw:1346125631014:dw| do you get it now?
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