Question

factor out in steps

3p^2-2p-5

Answer 1

For a problem like this I like to use what is known as the AC method.
You know that
ax^2+bx+c
is the samething right?

Answer 2

first break down the middle term
\[\implies 3p^2 - 5p + 3p - 5\]
now group them
\[\implies (3p^2 - 5p) + (3p - 5)\]
factor out...
\[\implies p(3p - 5) + (3p-5)\]
factor out again...
\[\implies (3p - 5)(p+1)\]
does that help?

Answer 3

explain the final two steps

Answer 4

wait what happend to the 2

Answer 5

\[(3p^2 - 5p) + (3p-5)\]
if you factor out p from \((3p^2 - 5p)\) you get \(p(3p - 5)\) got it?

Answer 6

yea

Answer 7

then now you have \[p(3p - 5) + (3p - 5)\]
this time 3p - 5 is common to both terms right?

Answer 8

yea

Answer 9

so if you factor out 3p - 5 you get 3p - 5)(p+1)

Answer 10

yeah i got it. just had a to remember back to my basic math. i feel so ashamed lol. well thanks

Answer 11

lol. welcome