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solve the diff equation. (y^-1)dy + (y*e^cos(x))*(sin(x))dx
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Equals zero?
yes ... =0
Thanks
It looks separable to me.
i got it to \[- e ^{\cos(x)} = y^{-1} +C\] is this correct first off?
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Yes.
i cannot figure out how to solve for y
Put the arbitrary constant on the other side. It is arbitrary, so it doesn't matter which side of the equation it is on.
Does that make sense?
but it is y^-1
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Well, if we have\[y^{-1}=C-e^{\cos(x)}\]We can simply take the reciprocal of both sides, provided that it doesn't equal zero:\[y=\frac{1}{C-e^{\cos(x)}}\]
alright thanks that's the answer.. couldn't figure out how to change it but it makes sense
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