Question

How do you simplify 9x^0 y^-8 over z^-8

Answer 1

hint: \[\huge \frac{9x^0 y^{-8}}{z^{-8}} \implies \frac{9x^0 z^8}{y^8}\]
i leave the simplifying to you

does that help?

Answer 2

How did you get the z^-8 and the y^-8 to be switched and then positive...also, I dont know what to do after that.

Answer 3

\[\huge y^{-a} \implies \frac 1{y^a}\]
so \[\huge y^{-8} \implies \frac{1}{y^8}\]

then \[\huge \frac 1{z^{-a}} \implies z^a\]
so \[\huge \frac{1}{z^{-8}} \implies z^8\]
got it?

Answer 4

Yeah I think so...is the answer 9x^0z^8 over y^8?

Answer 5

nope

Answer 6

what do you think is the value of x^0?

Answer 7

X?

Answer 8

the value of x^0 is x or is it 0?

Answer 9

it's 1. power to 0 is 1

Answer 10

anything raised to 0 is 1

Answer 11

So the answer would be 9xz^8 over y^8?

Answer 12

x^0 = 1

Answer 13

so x^0 will just disappear

Answer 14

and why it's 1 is a long explanation

Answer 15

\[\frac{a^b}{a^b} =a^{b-b}=a^0\]\[\frac{a^b}{a^b} = 1\]here's why it's 1 :P

Answer 16

Ohhh so it would be 9z^8 over y^8?

Answer 17

yup

Answer 18

Yay thank you! Can you tell me what type of equation this is so I can look it up in my textbook?