How do you simplify 9x^0 y^-8 over z^-8

Question

lgbasallote · Answer

hint: $$\huge \frac{9x^0 y^{-8}}{z^{-8}} \implies \frac{9x^0 z^8}{y^8}$$
i leave the simplifying to you

does that help?

emilyjones284 · Answer

How did you get the z^-8 and the y^-8 to be switched and then positive...also, I dont know what to do after that.

lgbasallote · Answer

$$\huge y^{-a} \implies \frac 1{y^a}$$
so $$\huge y^{-8} \implies \frac{1}{y^8}$$

then $$\huge \frac 1{z^{-a}} \implies z^a$$
so $$\huge \frac{1}{z^{-8}} \implies z^8$$
got it?

emilyjones284 · Answer

Yeah I think so...is the answer 9x^0z^8 over y^8?

lgbasallote · Answer

nope

lgbasallote · Answer

what do you think is the value of x^0?

emilyjones284 · Answer

X?

emilyjones284 · Answer

the value of x^0 is x or is it 0?

anonymous · Answer

it's 1. power to 0 is 1

lgbasallote · Answer

anything raised to 0 is 1

emilyjones284 · Answer

So the answer would be 9xz^8 over y^8?

lgbasallote · Answer

x^0 = 1

lgbasallote · Answer

so x^0 will just disappear

lgbasallote · Answer

and why it's 1 is a long explanation

anonymous · Answer

$$\frac{a^b}{a^b} =a^{b-b}=a^0$$$$\frac{a^b}{a^b} = 1$$here's why it's 1 :P

emilyjones284 · Answer

Ohhh so it would be 9z^8 over y^8?

lgbasallote · Answer

yup

emilyjones284 · Answer

Yay thank you! Can you tell me what type of equation this is so I can look it up in my textbook?