(-1, 3) and perpendicular to y = -1/3x + 7. y = 3x - 12 y = 3x + 6 y = 3x - 6 y = 3x
i might as well just teach you everything about lines......
parallel lines share the same slope perpendicular lines slopes are negative reciprocals of each other ex. if one line had a slope of 2, the perpendicular line would have a slope of -1/2 Point slope form \[y-y_1=m(x-x_1)\] when ever you are trying to find the equation of a line and you're given the slope and a point, substitute those into the point slope form then solve for y to get slope intercept form \[y=mx+b\] where m is the slope and b is the y intercept
what do i do to start??
find the slope of the perpendicular line
the slope ofy = -1/3x + 7 ???? its -1/3
so the negative reciprocal of -1/3 is?
3?
so the slope of your perpendicular line is 3 now you have a point and a slope, substitute those into the point slope form
what do i substitute with what???????????
(-1, 3) and m=3 into y-y1...
mmmmmm
he's referring to the point slope form. \[y-y1=m(x-x1)\] We now know that m=3, x1=-1 and y1=3 \[y-3=3(x+1)\] Solve for y.
y = 3?
\[y=3x+3+3\]
what do you get?
y = 3 (x + 2)
Yes. But what is your answer?
y = 3x + 6
yes.
thank you
you're welcome.
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