Question

Determine the horizontal and vertical asymptotes for the following functions:
a) g(x) = sin(x-pi/4)
b) h(x) = sin x/2
c) j(x) = 2 sin x - 1

Answer 1

@Hero
@lgbasallote
@experimentX

plz help guys !

Answer 2

asymptotes for sin and cos functions ??

Answer 3

yes

Answer 4

they are never undefined and functions never approach infinity....thus vertical asymptote does not exist

Answer 5

for such kinda function, you have envelopes than asymptotes

Answer 6

i want to know only about asymptotes

Answer 7

the horizontal and vertical?

Answer 8

are you sure you don't want to know about periods and phase shifts ?

Answer 9

only asymptotes ...
i know period and phase shifts

Answer 10

http://www.sagemath.org/calctut/inflimits.html

Answer 11

info about oscillating functions is below

Answer 12

ok .. what about your opinions regarding asymptotes ...
the knowledge which you know regarding them?

Answer 13

I don't think it would have one.

Answer 14

none of those functions have vertical asymptotes..... there is no "c" such that \(\large \lim_{x \to \infty } f(x) = \pm\infty\)

Answer 15

likewise for horizontal asymptotes, there is no "c" such that:
\(\large \lim_{x \to \infty}f(x)=c \)

Answer 16

\[\large \lim_{x \to c} f(x) = \pm\infty\]

Answer 17

i could never get that "c apporoach infinity" under the limit... thanks X.... :)

Answer 18

@ hero?

Answer 19

@Hero ... help

Answer 20

then?

Answer 21

then see there is no asymptote:)

Answer 22

soorry but i can't graph on calculator

Answer 23

just tell me from basic definition

Answer 24

did u know it or not ?

Answer 25

then how can i find for sin and cosine functions?

Answer 26

graph or think about 1/x note x can never equal 0 but it can get as close as it does, and as its closer and closer 1/x shoots up to infinity. ps you can graph things on the internets for free thus no need to own a calculator if you have the interwebs and to me it looks as if you do:)

Answer 27

there is no asymptots for cos(x) and sin(x) there is however for sin(x)/x for the same reason as 1/x

Answer 28

graph or think about 1/x note x can never equal 0 but it can get as close as it does,

should read

graph or think about 1/x note x can never equal 0 but it can get as close as it wants.

Answer 29

i think you all don't know how to do it ...

Answer 30

lol ok go with that and go figure it out and get back to us, as you have just broke math if you find it:)

Answer 31

we have given you the answers you just need to think about it.

Answer 32

think about 1/.0000000000000000000001

what does that equal?

Answer 33

now add 50 0's

Answer 34

this is the cause of such asymptotes

Answer 35

your answers are not making sense with the question which i had written ....
you all are telling me the basic definition of asymptote

Answer 36

because you ask a question that does not make sense. It is sort of like me asking you to tell me when the function f(x) = 3 is equal to 0. it just never is....

Answer 37

go graph them...wolfram alpha will do it for free:)

Answer 38

@zzr0ck3r my question doesn't make sense ... what ??
go...... first study asymptotes of trigonometric functions .. then give your suggestions...

Answer 39

i think this website is just for students of lower grades not for ..

Answer 40

@Hero ... .where are u?
how u got 99 smartscore?

Answer 41

lol, listen like 5 really smart people have told you what is going on. you refuse to listen. Not all trig functions have asymptotes such as sin(x) (does not) while sin(1/x) does.

Answer 42

im pretty sure your just trolling at this point...so good luck with all that. when you want to learn about math let us know. gl

Answer 43

http://www.wolframalpha.com/input/?i=sin(x-pi%2F4)&t=crmtb01

Answer 44

how u got sin x does not have asymptote?

Answer 45

yes and notice you can draw that whole graph without lifting your pen, thus no asymtote. go graph

sin(x) then graph sin(1/x) note the difference of the two and how sin(1/x) shoots of to infinity and sin(x) does not.

Answer 46

Instead of complaining, try to understand what an asymptote is first.

Answer 47

amen, again good luck. And again, those dudes ^^^^ with the 99's really seem to know what they are talking about:)

Answer 48

i am disappointed...

Answer 49

This has to be a joke.

Answer 50

its true...

Answer 51

Tell me pls what is the problem - with your "humor" i mean