A block of mass m slides down on rough inclined plane of angle x with the horizontal with an acceleration "a" along the plane the value of reaction is?

Question

anonymous · Answer

It is un-allowed to give the final answer here, so I state the direction only:
a. Separate the tangential and the normal components of the weight
b. The normal component = the reaction
c. The tangential component = Weight * Sin x

anonymous · Answer

and wat does..." Reaction" here means?

anonymous · Answer

is it abt Normal Reaction

anonymous · Answer

yep

anonymous · Answer

i guess It is Mg cos x

anonymous · Answer

The third Newton's law says that the slope surface pushes back the weight of the block (only the normal component of it, of course) this IS the Reaction

anonymous · Answer

Mr Yahoo note that You were not given the Mg - only the a, so use points a,b,c above

anonymous · Answer

I could spell the answer - but it is unallowed here

anonymous · Answer

Should be Consider Friction..here

anonymous · Answer

No because it is NOT mentioned - so you read it "no friction"

anonymous · Answer

Use my points a,b,c above. Write an appropriate formula (you actually written it here ...) and solve for Normal force

anonymous · Answer

Strange - I was banned for giving complete solution - but no reprimand is given here by the moderators ....

anonymous · Answer

The answer should be

$$m \sqrt{g^2 + a^2 - 2 a g sinx}$$

anonymous · Answer

why the Normal Reaction can't be Mg cosx

anonymous · Answer

IT is

anonymous · Answer

Did nt... Understand..Wat u r trying to say..

anonymous · Answer

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