Question

If a min force of 500N is req to move a box of mass 100kg resting on horizontal floor the coefficient of friction b/w the box and the floor is (g=10m/s^2)

Answer 1

I got U = 1/2.........But the answer should be 1/sqrt3

Answer 2

@Mikael @RaphaelFilgueiras @experimentX

Answer 3

@sami-21

Answer 4

500=m*g*U
u=500/(100*10)

Answer 5

if u write N=U.m.g.sin 60,then u get U=1/(sqrt 3),but i don't know how we could get sin 60 there.....

Answer 6

i think...may be the answer Given is wrong..))