Question

A body Slide down a fixed rough inclined plane that is at an angle of 45 degree with the horizontal. The distance x travelled by the body in time t is given by x = sqrt3 t^2 the coefficient of the friction b/w the body and the inclined surface is?

Answer 1

@sami-21 @hartnn @RaphaelFilgueiras @Mikael

Answer 2

calculate double derivative

Answer 3

which gives you acceleration

Answer 4

a = 2*sqrt3

Answer 5

i draw the free body diagram.. wait a moment.

Answer 6

Cf = coefficient of friction..
did you understand the forces ?

Answer 7

oh..sorryy

Answer 8

u r correct

Answer 9

why cut it.... Friction force = Cf * N

Answer 10

Sorry..

Answer 11

Go..On

Answer 12

mg sin45 - mg cos45 = ma

Answer 13

yeah put value of a from double derivative..

Answer 14

sorry mg sin45 - Umg cos45 = ma

Answer 15

u have m , g , sin45,cos45 and a... calculate U xD

Answer 16

Cheers!

Answer 17

Yup......thxzxxxx