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OpenStudy (honeymonster):
ok..how do i make x the subject of the formula when fractions are involved :S..... equation posted in replies..
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OpenStudy (honeymonster):
\[\frac{ 1 }{ x } + \frac{ 1 }{ y } = 1\]
hartnn (hartnn):
since 1/y is added,first u can subtract 1/y from both sides..what will u get?
OpenStudy (honeymonster):
1/x =y
hartnn (hartnn):
nopes,u should subtract 1/y to 1,like this
\[\frac{1}{x}=1-\frac{1}{y}\]
got this?
OpenStudy (honeymonster):
oh ok...so would you then multiply?
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hartnn (hartnn):
multiply what?
OpenStudy (honeymonster):
the fractions to cancel them out? :S or am i going completely the wrong direction?
hartnn (hartnn):
ok,i will show u next step,see if u can understand:
\[\frac{1}{x}=\frac{y-1}{y}\]
got this?
OpenStudy (honeymonster):
ok i understand that bit..
hartnn (hartnn):
now since there is 1/x which is reciprocal of x,
i would just invert both sides like this:
\[x=\frac{y}{y-1}\]
got this?
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OpenStudy (honeymonster):
ok..i think i get that..so basically you would just swap the top and the bottom numbers on the right side?
hartnn (hartnn):
yes,because there was 1/x on left side
and u did the same thing on both sides.
OpenStudy (honeymonster):
ok thank you :)
hartnn (hartnn):
welcome :)
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