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i have struggled with this for a while so please help..how to make x the subject of the formula posted in replies..
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\[\frac{ 1 }{ x+1 } - \frac{ 1 }{ y-1 } =1\]
\[1\div \left( x+1 \right)=1\div \left( y-1 \right)+1\]
can you add the right side in \[ \frac{1}{x+1}= 1+\frac{1}{y-1} \] ?
by using a common denominator of y-1
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possibly..not completely sure..sorry
try. multiply the 1 by (y-1)/(y-1) then add the tops and keep the same bottom
\[1=(x+1)[\frac{ 1 }{ y-1 }+1]\] \[\frac{ 1 }{ \frac{ 1 }{ y-1 }+1 }=x+1\] \[\frac{ 1 }{ \frac{ 1 }{ y-1 }+1 }-1=x\]
I'm pretty sure that's correct.
And you couldn't use y-1 as a common denominator unless you made all the elements of the equation have a denominator of y-1
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ok thank you everybody :)
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