A 0.4243-g sample of CaCO 3 is dissolved in 12 M HCl and the resulting solution is diluted to 250.0 mL
in a volumetric flask.How many moles of CaCO 3 are used (formula mass = 1 00.1 )?

Question

A 0.4243-g sample of CaCO 3 is dissolved in 12 M HCl and the resulting solution is diluted to 250.0 mL
in a volumetric flask.How many moles of CaCO 3 are used (formula mass = 1 00.1 )?

goformit100 · Answer

Hint : Use Mole Concepts

anonymous · Answer

STEP I) First write the equation for the reaction to see how many moles of CaCO3 react with 1 mole HCl.
STEP II) Then find the number of moles of CaCO3 in 0.4243 gms. Corresponding to this you can estimate how many moles of 12M HCl would have been used.
STEP III) The molarity of HCl sample tells you how many moles of HCl were originally available for the reaction, whichever is lesser than the required quantity (as obtained from steps i and ii) would decide the answer; that is whether all the available moles of CaCO3 (From STEP I)were used or not.|dw:1346218182472:dw|