Can someone help me solve step by step, I need to find the domain.. g(t)=sqrt(3-t) - sqrt(2+t)
sqrt(x) will not give real numbers when x is negative,that is when x<0 u got this?
uhm, no. That confused me. I know that you cannot have a zero with sqrt.. is that what you mean?
i mean sqrt(-1) or sqrt(-3) is not real. or any negative numbers' square root is not real,so that would not be included in the domain. ok?
oh okay. that makes sense.
so t cannot be anything less than 3?
if t is 1 then 3-1=2 is positive,so t can be less than 3. what u have to do is to make x>0 in sqrt(x) so here 3-t>0 is your domain for 1st term.
I mean t can't be greater than 3
ok? so t<3 is actually your domain for 1st term now can u work out second term for me?
yes,thats correct then
t cant be less than -1?
where did -1 come from ?? i see 2+t>0
t>-2?
t<-2 lol
its t>-2 ok? can we go ahead?
is it 3>t>-2?
{3>t>-2}
yes.do u have options?
nope, I have to solve it... not multiple choice or anything.
then i will give u a set notation to write the domain: |dw:1346186867205:dw| thats read as for all x,such that t belongs to Real numbers,t greater than -2 and less than 3. got it?
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