Question

Write the equation of the line that passes through (1, 3) and (4, 4) in standard form.

Answer 1

3x – 3y = –8
x – 3y = –9
x – 3y = –8
3x + y = 9

Answer 2

3x – 3y = –8


x – 3y = –9


3x + y = 9


x – 3y = –8

Answer 3

it looks different

Answer 4

the equation of line can be written as (y-y1)=m(x-x1)
where (x1,y1) is a point on that line.
so put any one of the points here and tell me what u get.

Answer 5

(3, 1)

Answer 6

@paulaaa

Answer 7

@Hero can u save me pleeeeeeeeeease

Answer 8

Plug each of the points one at a time into the equation y = mx + b

Answer 9

how old r u
i did that

Answer 10

You should end up with

4 = 4m + b
3 = 1m + b

Answer 11

i got that

Answer 12

Now isolate b in each equation

Answer 13

Let me know what you get

Answer 14

i got -9

Answer 15

sorry i didnt get notified intell know but it looks like u dont need my help u got hero so nvm

Answer 16

You isolated b in each equation and got -9?

Answer 17

You should have gotten

b = 4 - 4m
b = 3 - 1m

Answer 18

i dont get it

Answer 19

Write the equation of the line that passes through (1, 3) and (4, 4) in standard form.

one way is find the slope: (4-3)/(4-1) = 1/3
find b (y intercept)
y= mx + b with m= 1/3 use (1,3) , x=1, y=3 to find b
3= (1/3)*1+b
b= 3- (1/3) = 8/3

so the equation is y= (1/3) x + 8/3

now put into standard form (x is first, positive coefficient)

Answer 20

Plug each (x,y) point into the equation y = mx + b to get two equations:
4 = 4m + b
3 = 1m + b

Isolate b in each equation to get

b = 4 - 4m
b = 3 - 1m

set b = b to get

4 - 4m = 3 - 1m

Place like terms on the same side to get
4 - 3 = 4m - 1m

Simplify to get
1 = 3m

Isolate m = to get
1/3 = m

Subsitute m back into one of the equations above to solve for b:

b = 3 - 1m
b = 3 - 1(1/3)
b = 9/3 - 1/3
b = 8/3

Now that you've found m and b, write the equation of the line in the form y = mx+ b:
y = x/3 + 8/3