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Find the volume of a square pyramid with base edges of 48 cm and a slant height of 26 cm.
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A. 11,520 cm3 B. 23,040 cm3 C. 7,680 cm3 D. 768 cm3
first define the volume of a pyramid in an equation
\[V=\frac{ 1 }{ 3 }s ^{2}h\]
then figure out the height, do u know how to do that?
Volume of any body = (area of base) x (height). We have the side of the base square = 48 cm, so area of base A is \[A = 48 \times 48 cm^2 = 2304 cm^2 \] From the slant height we'll find the height using Pythagoras theorem in triangle ABC|dw:1346190964787:dw| \[26^2 = 24^2 + h^2\] find h and use V = A x h
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