Show that the equation represents a circle by rewriting it in standard form, and find the center and radius of the circle. 3x2 + 3y2 − 7x = 0
complete the square
Thats your hint
Yeah I did that, you get (x^2 -7/3x +49/36) + y^2 = 49/36
You need to put it in standard form
So you tell me what subtracts into -7/3x and multiplies into 49/36
No I don't.. It's a circle.
Yes, you do.
You're almost done.
Standard form of a circle is (x-h)^2 + (y-k)^2 = r^2
It's not that difficult
Exactly. You need to put the expressions with the x's in that same form
Yeah, so can you tell me what subtracts into 7/3 and multiplies into 49/36. Because it's obviously not Radical 7/3
Basically you're telling me you're having trouble finding the perfect square form of the expression.
basically I am telling you I don't know the Binomial expression. I have the polynomial quadratic, I just can't fathom any number that completes that into a binomial expression.
I can't fathom how you completed the square without figuring out what the binomial expression is. I'll finish it for you.
nvm got it.
Well, what is it then?
(x-7/6)^2 + y^2 = 49/36 so center is 7/6,0 radius is 7/6
That is correct.
I wonder what it was that was holding you back.
My brain fart probably.. and the fact I hate staring at fractions.
If I were you, I'd write the final form this way: \[(x - \frac{7}{6})^2 + y^2 = (\frac{7}{6})^2\]
The professor wants it in r^2 format so I keep it in r^2
That is r^2 form
No I mean he wants it completely written out.,
It's not that big a deal anyway
If I were the instructor, either way would be fine with me.
Just as long as you know how to do it.
Well you aren't a raging asian.. so I am not going to fight with him you know?
Raging asian? I haven't seen one of those since a kid got smacked by the teacher.
Thats what I feel he will do.. haha
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