Ask your own question, for FREE!
Mathematics 13 Online
OpenStudy (anonymous):

How do you find a vector of length 10 in the direction of v= <3,-2>?

OpenStudy (anonymous):

Do you know how to find a unit vector in that direction?

OpenStudy (anonymous):

v/|v| but i dont know what that means

OpenStudy (anonymous):

You don't know what that formula means or you don't know how that helps?

OpenStudy (anonymous):

I don't know what it means, I assume the |v| is the magnitude so 3^2+-2^2=13 but i dont know v

OpenStudy (anonymous):

Correct. \(\mathbf{v}\) is just your \(\langle 3, -2 \rangle\), so a unit vector (vector of length 1) in the direction of \(\mathbf{v}\) is \(\langle 3/13, -2/13\rangle\). So if we want a vector of length 10, what do you think we do?

OpenStudy (anonymous):

multiply by 10?

OpenStudy (anonymous):

thanks

OpenStudy (anonymous):

Perfect.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!