Solve the absolute. There should be 2, if not 1. Show work and instructions: 3|2A + 7| = 3A + 12
1. Divide both sides by 3. Let me know what you get
2A + 7 = 3A + 4
You divided both sides by 3. That doesn't mean get rid of the absolute value just yet.
oh okay
So what do you have so far?
|2A + 7| = 3A + 4
Okay, so for the next step, apply this rule: If |a + b| = c , then a + b = ±c
I just need the steps to the problem
And I am guiding you through the steps.
yes, but a + b = c will confuse me
I wonder what's so difficult about applying the rule so that afterwards you get 2A + 7 = ±(3A + 4)
I just need the steps and answer or I won't get it. Yes I got answer
I am in algebra 2, we didn't have to put +/- by anything unless it's positive/negative
so the end is 2A + 7 = 3A + 4 and 2A + 7 = -3A - 4 just solve those equations for A
which A do I +/-
Doesn't matter. As long as you put the A's on one side and the constants on the other (the numbers without variables) So A = 3 and 2A + 3A = -4 - 7 5A = -11 A = -11/5
can you work out the problem, so I could see
I got A = -3
2A - 3A = 4 - 7 -A = -3 A = 3
I am getting a positive A not a negative
2A - 3A = -A or are you not getting 2A - 3A
no I am it's just I missed interperted
it
sorry
so do you know how I got -A now?
yea! I am sorry @ArkGoLucky
no no it's fine
absolute values can be confusing
I just calculated it wrong cause I am tired
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