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Find the General Solution with the given Initial Condition: y'+(2/t)y=(cost t)/t^2 y(pi)=0 t>0
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Integration Factor: \[\mu(t)=\int\limits\limits e ^{ \frac{ 2 }{ t }}\]
i think you wrote it little bit different should be \[\Large I.F=e^{\int\limits_{}^{} \frac{2}{t}dt}\]
ya that, but i just discovered that wolfram does these :)
yes it does!
medal for a medal lol:)
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it is false
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