verify that the function f(X)=x^3-7 and g(X)=3sqrt x+7 are inverse of each other
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OpenStudy (lgbasallote):
do you know how to solve for f(g(x))?
OpenStudy (anonymous):
yes
OpenStudy (lgbasallote):
good. first, let me tell you the concept
they are inverse if:
f(g(x)) = g(f(x))
so to verify...you need to solve for f(g(x)) and g(f(x)) and see if they are equal
does that help?
OpenStudy (anonymous):
i try first , k?
OpenStudy (lgbasallote):
sure
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OpenStudy (anonymous):
f[g(X)]=f(3sqr [x+7]]
OpenStudy (lgbasallote):
yes go on... substitute \(3\sqrt{x+7}\) into the x of x^3 - 7
OpenStudy (anonymous):
f(g(X))=(3sqrt x+7)^3 -7 , i dont no how to solve this
OpenStudy (lgbasallote):
one question first... is that \[3\sqrt{x+7}\]or \[3\sqrt x + 7\]
OpenStudy (anonymous):
the first one
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OpenStudy (lgbasallote):
oh cool.
anyway...try solving g(f(x)) first if you're stuck here. you dont know...it might look like that too
sam (.sam.):
Actually you can just solve for f(X)=x^3-7
Let y=x^3-7
y+7=x^3
\[\sqrt[3]{y+7}=x\]
\[f^{-1}(x)=\sqrt[3]{x+7}=g(x)\]