Question

A chain of lenght 1m lying lenghtwise on a fixed table is partially hanging vertically outside the edge of the table . If the coefficient of friction b/w chain and the table is 0.5 the max lenght of the chain that can hang from the table without slipping?

Answer 1

let the mass per unit length of the chain = m then mass of length x = m*x and it's weight= m*x*g

Answer 2

to find the maximum length...just equate weight of hanging chain= force of friction...because if is the force of friction that will stop chain from slipping and force of friction= u* normal= 0.5* m(1-x)*g

Answer 3

your final equation is \[0.5*m(1-x)g= m*x*g\] hope this helps you :)

Answer 4

@Yahoo! did you get 0.33m

Answer 5

wat would be its mass

Answer 6

you can't calculate mass ...don't worry it will be canceled on both sides

Answer 7

@Yahoo! check out the above equation

Answer 8

oh ...yup.....u explained this....so...well..lol

Answer 9

:)

Answer 10

thxxx a lot

Answer 11

you're welcome