```
a_string = 'abc'

destination = [2, 3]

edges = { (1, 'a') : [2, 3],
(2, 'a') : [2],
(3, 'b') : [4, 3],
(4, 'c') : [5] }

def make(a_string, destination, edges):
n = 0
while n + 1

Question

```
a_string = 'abc'

destination = [2, 3]

edges = { (1, 'a') : [2, 3],
          (2, 'a') : [2],
          (3, 'b') : [4, 3],
          (4, 'c') : [5] }

def make(a_string, destination, edges):
    n = 0
    while n + 1 < len(a_string):
        letter = a_string[n]
        letter2 = a_string[n + 1]
        for d in destination:                              # (1)
            if (d, letter2) in edges:
                for state in edges[(d, letter2)]:
                    destionation.append(state)
            destination.remove(d)
        n += 1                                             # (2)
    return destination
```

The code return [], but I expect to see [5], so I think the problem is that it increment n unexpectedly then make letter2 change. Why does this code increment n (at position 2) before completing the for loop (at position 1)?

farmdawgnation · Answer

I don't know python, but I put it in a code block for you to make it easier to read and so it would highlight. :)

anonymous · Answer

ok, thank you.

tyteen4a03 · Answer

Can you describe the function a bit more?

rsmith6559 · Answer

Are you sure that you're getting what you expect as destination when the function is called?  You have no test, it's just a blind iteration.  Just for debugging, why not print out string, destination and edges to make sure of your data?

anonymous · Answer

OK, now I think it is clearer